Codeforces 112A Petya and Strings Solution in C

1. #include<stdio.h>
2. #include<string.h>
3. int main()
4. {
5. int x, i,o,l;
6. x=0;
7. char a[200],b[200];
8. scanf("%s %s",&a,&b);
9. l=strlen(a);
10. for (i=0;i<l;i++)
11. {
12. o=a[i]-b[i];
13. if (o!=0 && o!=32 && o!=-32)
14. {
15. if (a[i]<='z' && b[i]<='z' && a[i]>='a' && b[i]>='a')
16. {
17. if (a[i]>b[i])
18. {
19. x=1;
20. break;
21. }
22. else
23. {
24. x=-1;
25. break;
26. }
27. }
28. if (a[i]<='Z' && b[i]<='Z' && a[i]>='A' && b[i]>='A')
29. {
30. if (a[i]>b[i])
31. {
32. x=1;
33. break;
34. }
35. else
36. {
37. x=-1;
38. break;
39. }
40. }
41. if (a[i]<='Z' && a[i]>='A' && b[i]<='z' && b[i]>='a')
42. {
43. if (a[i]+32>b[i])
44. {
45. x=1;
46. break;
47. }
48. else
49. {
50. x=-1;
51. break;
52. }
53. }
54. if (a[i]<='z' && a[i]>='a' && b[i]<='Z' && b[i]>='A')
55. {
56. if (a[i]-32>b[i])
57. {
58. x=1;
59. break;
60. }
61. else
62. {
63. x=-1;
64. break;
65. }
66. }
67. }
68. }
69. printf("%d\n",x);
70. return 0;
71. }