- #include<stdio.h>
- #include<string.h>
- int main()
- {
- int i,a,b,c,x,z;
- char n[200];
- scanf("%s",&n);
- x=strlen(n);
- i=0;a=0;b=0;c=0;
- while (i<x)
- {
- if (n[i]=='1') a++;
- else if (n[i]=='2') b++;
- else if (n[i]=='3') c++;
- i+=2;
- }
- i=0;z=0;
- while (i<a)
- {
- if (i==0) printf("1");
- else printf("+1");
- i++;
- z++;
- }
- i=0;
- while (i<b)
- {
- if (z==0) printf("2");
- else printf("+2");
- i++;
- z++;
- }
- i=0;
- while (i<c)
- {
- if (z==0) printf("3");
- else printf("+3");
- i++;
- z++;
- }
- printf("\n");
- return 0;
- }
Tuesday, January 21, 2020
Codeforces 339A Helpful Maths Solution in C
Codeforces 96A Football Solution in C
- #include<stdio.h>
- #include<string.h>
- int main()
- {
- int i,o,p=0;
- char n[700];
- scanf("%s",&n);
- o=strlen(n);
- for (i=0;i<o-6;i++)
- {
- if (n[i]=='0' && n[i+1]=='0' && n[i+2]=='0' && n[i+3]=='0' && n[i+4]=='0' && n[i+5]=='0' && n[i+6]=='0')
- {
- p=7;
- break;
- }
- if (n[i]=='1' && n[i+1]=='1' && n[i+2]=='1' && n[i+3]=='1' && n[i+4]=='1' && n[i+5]=='1' && n[i+6]=='1')
- {
- p=7;
- break;
- }
- }
- if (p==7) printf("YES\n");
- else printf("NO\n");
- return 0;
- }
Codeforces 112A Petya and Strings Solution in C
- #include<stdio.h>
- #include<string.h>
- int main()
- {
- int x, i,o,l;
- x=0;
- char a[200],b[200];
- scanf("%s %s",&a,&b);
- l=strlen(a);
- for (i=0;i<l;i++)
- {
- o=a[i]-b[i];
- if (o!=0 && o!=32 && o!=-32)
- {
- if (a[i]<='z' && b[i]<='z' && a[i]>='a' && b[i]>='a')
- {
- if (a[i]>b[i])
- {
- x=1;
- break;
- }
- else
- {
- x=-1;
- break;
- }
- }
- if (a[i]<='Z' && b[i]<='Z' && a[i]>='A' && b[i]>='A')
- {
- if (a[i]>b[i])
- {
- x=1;
- break;
- }
- else
- {
- x=-1;
- break;
- }
- }
- if (a[i]<='Z' && a[i]>='A' && b[i]<='z' && b[i]>='a')
- {
- if (a[i]+32>b[i])
- {
- x=1;
- break;
- }
- else
- {
- x=-1;
- break;
- }
- }
- if (a[i]<='z' && a[i]>='a' && b[i]<='Z' && b[i]>='A')
- {
- if (a[i]-32>b[i])
- {
- x=1;
- break;
- }
- else
- {
- x=-1;
- break;
- }
- }
- }
- }
- printf("%d\n",x);
- return 0;
- }
Codeforces 282A Bit++ Solution in C
- #include<stdio.h>
- #include<string.h>
- int main()
- {
- int i,j,k,n,s;
- char x[7];
- scanf("%d",&n);
- j=0;
- k=0;
- for (i=0;i<n;i++)
- {
- scanf("%s",&x);
- if (x[0]=='+' || x[2]=='+')
- {
- j++;
- }
- else
- {
- k++;
- }
- }
- s=j-k;
- printf("%d\n",s);
- return 0;
- }
Codeforces 50A Domino piling Solution in C
- #include<stdio.h>
- int main()
- {
- int x,y,p,s,a=0,b=0;
- scanf("%d%d",&x,&y);
- if (x>=1 && x<=y && y<=16)
- {
- p=x*y;
- while (p>a)
- {
- a=a+2;
- if (a<=p) b++;
- }
- printf("%d\n",b);
- }
- return 0;
- }
Codeforces Problem 231A Team Solution in C
- #include<stdio.h>
- int main()
- {
- int i,j,a,b,c,x,y=0;
- scanf("%d",&i);
- if (i>0 && i<=1000)
- {
- for (j=0; j<i; j++)
- {
- scanf("%d %d %d",&a,&b,&c);
- if ((a==1 || a==0) && (b==1 || b==0) && (c==1 || c==0))
- {
- x=a+b+c;
- if (x>=2) y++;
- }
- }
- printf("%d\n",y);
- }
- return 0;
- }
Codeforces 118A String Task in C
Hi! I'm Sujan Mridha, the solution of 118A String Task is given below:
- #include<stdio.h>
- int main()
- {
- int l,i;
- char a[200];
- scanf("%s",&a);
- l=strlen(a);
- for (i=0; i<l; i++)
- {
- if (a[i]>='A' && a[i]<='Z') a[i]=a[i]+32;
- if (a[i]!='a' && a[i]!='A' && a[i]!='E' && a[i]!='e' && a[i]!='I' && a[i]!='i' && a[i]!='o' && a[i]!='O' && a[i]!='U' && a[i]!='u' && a[i]!='y' && a[i]!='Y') printf(".%c",a[i]);
- }
- printf("\n");
- return 0;
- }
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